Se \(\LARGE f_0 = \frac{x}{x+1}\) e \(\LARGE f_0 \circ f_{n}\) para n = 0, 1, 2, ... então \(\LARGE f_{n}(x)\) vale
\(\LARGE \frac{x}{x+n}\)
\(\LARGE \frac{(n+1)x}{x+1}\)
\(\LARGE \frac{nx}{x+1}\)
\(\LARGE \frac{x}{(n+1)x+1}\)
\(\LARGE \frac{x}{nx+1}\)